Java XPath解析器 - 查詢XML文檔
演示示例
這是我們需要查詢輸入的文本文件:
<?xml version="1.0"?> <class> <student rollno="393"> <firstname>dinkar</firstname> <lastname>kad</lastname> <nickname>dinkar</nickname> <marks>85</marks> </student> <student rollno="493"> <firstname>Vaneet</firstname> <lastname>Gupta</lastname> <nickname>vinni</nickname> <marks>95</marks> </student> <student rollno="593"> <firstname>jasvir</firstname> <lastname>singn</lastname> <nickname>jazz</nickname> <marks>90</marks> </student> </class>
演示示例:
XPathParserDemo.java
package com.yiibai.xml; import java.io.File; import java.io.IOException; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.ParserConfigurationException; import javax.xml.xpath.XPath; import javax.xml.xpath.XPathConstants; import javax.xml.xpath.XPathExpressionException; import javax.xml.xpath.XPathFactory; import org.w3c.dom.Document; import org.w3c.dom.NodeList; import org.w3c.dom.Node; import org.w3c.dom.Element; import org.xml.sax.SAXException; public class XPathParserDemo { public static void main(String[] args) { try { File inputFile = new File("input.txt"); DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder dBuilder; dBuilder = dbFactory.newDocumentBuilder(); Document doc = dBuilder.parse(inputFile); doc.getDocumentElement().normalize(); XPath xPath = XPathFactory.newInstance().newXPath(); String expression = "/class/student[@rollno='493']"; NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET); for (int i = 0; i < nodeList.getLength(); i++) { Node nNode = nodeList.item(i); System.out.println("\nCurrent Element :" + nNode.getNodeName()); if (nNode.getNodeType() == Node.ELEMENT_NODE) { Element eElement = (Element) nNode; System.out.println("Student roll no : " + eElement.getAttribute("rollno")); System.out.println("First Name : " + eElement .getElementsByTagName("firstname") .item(0) .getTextContent()); System.out.println("Last Name : " + eElement .getElementsByTagName("lastname") .item(0) .getTextContent()); System.out.println("Nick Name : " + eElement .getElementsByTagName("nickname") .item(0) .getTextContent()); System.out.println("Marks : " + eElement .getElementsByTagName("marks") .item(0) .getTextContent()); } } } catch (ParserConfigurationException e) { e.printStackTrace(); } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (XPathExpressionException e) { e.printStackTrace(); } } }
這將產生以下結果:
Current Element :student Student roll no : 493 First Name : Vaneet Last Name : Gupta Nick Name : vinni Marks : 95